| Tubes |
---|
Dilution | 1 | 2 | 3 |
---|
10-5
| 0 | 0 | 0 |
10-4
| 0 | 0 | 0 |
10-3
| 0 | + | 0 |
10-2
| + | + | + |
10-1
| + | + | + |
100
| + | + | + |
- The mean fertile level (X) = no. of fertile cultures (10) / no. of cultures at each level (3). K = 0.760 from Table [6].
- Log pnb = X-K + log5 (organ in 5 ml) = 3.272